14c^2-19c-3=0

Solution for 14c^2-19c-3=0 equation:

Simplifying
14c2 + -19c + -3 = 0

Reorder the terms:
-3 + -19c + 14c2 = 0

Solving
-3 + -19c + 14c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-1 + -7c)(3 + -2c) = 0

Subproblem 1
Set the factor '(-1 + -7c)' equal to zero and attempt to solve:

Simplifying
-1 + -7c = 0

Solving
-1 + -7c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -7c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -7c = 0 + 1
-7c = 0 + 1

Combine like terms: 0 + 1 = 1
-7c = 1

Divide each side by '-7'.
c = -0.1428571429

Simplifying
c = -0.1428571429
Subproblem 2
Set the factor '(3 + -2c)' equal to zero and attempt to solve:

Simplifying
3 + -2c = 0

Solving
3 + -2c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + -2c = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -2c = 0 + -3
-2c = 0 + -3

Combine like terms: 0 + -3 = -3
-2c = -3

Divide each side by '-2'.
c = 1.5

Simplifying
c = 1.5
Solution
c = {-0.1428571429, 1.5}